https://file.aiquickdraw.com/mathbot/file/1728498992946uhqfreq8.jpg

The image shows a triangle with three angles, all labeled in terms of \( p \):

- One angle is \( p - 48^\circ \),
- Another is \( p \),
- The third is \( p - 45^\circ \).

We know that the sum of the interior angles in any triangle is always \( 180^\circ \). So, we can write the equation:

\[
(p - 48^\circ) + (p - 45^\circ) + p = 180^\circ
\]

Let's simplify the equation:

\[
p - 48 + p - 45 + p = 180
\]

\[
3p - 93 = 180
\]

Now, solve for \( p \):

\[
3p = 180 + 93
\]

\[
3p = 273
\]

\[
p = \frac{273}{3} = 91
\]

Thus, \( p = 91^\circ \).

Let me know if you'd like more details or have further questions!

Here are five related questions:
1. What is the value of each angle in the triangle now that \( p = 91^\circ \)?
2. How does the triangle classification change if any of these angle values were adjusted?
3. Can you explain why the sum of the angles in a triangle is always \( 180^\circ \)?
4. How would this problem change if one of the angles was an obtuse angle?
5. How would you check for calculation errors in problems like these?

**Tip**: Always check your solution by summing the angles to ensure they add up to \( 180^\circ \).

Learn how to find the value of p in a triangle where the angles are expressed as p, p - 48°, and p - 45°. This solution uses the sum of angles in a triangle to solve for p, making it a great practice problem for students in Grades 6-8.

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