Math Problem Statement
Find the exact location of all the relative and absolute extrema of the function. (Order your answers from smallest to largest x.) f(x) = 3x2 − 12x + 3 with domain [0, 3] f has at (x, y) =
. f has at (x, y) =
. f has at (x, y) =
.
Solution
To find the exact location of the relative and absolute extrema of the function on the interval , we can follow these steps:
Step 1: Find the first derivative of the function
The first derivative, , will help us identify critical points where the slope of the function is zero or undefined.
Step 2: Set the first derivative equal to zero
To find critical points, set :
Solve for :
Thus, is a critical point.
Step 3: Evaluate the function at the endpoints of the domain and at the critical point
The function is defined on the closed interval , so we need to evaluate at both endpoints of the interval as well as at the critical point .
Step 4: Determine the relative and absolute extrema
Now, we compare the function values at the critical point and the endpoints:
-
-
-
-
The absolute maximum value is , which occurs at .
-
The absolute minimum value is , which occurs at .
-
The relative maximum is not present because the function is continuously decreasing after the critical point .
Final Answer
- has an absolute maximum at .
- has a relative minimum at .
- has an absolute minimum at .
Would you like more details or have any further questions on this? Here are some related topics to explore:
- How to identify critical points of a function.
- The first and second derivative tests for extrema.
- How to check for concavity and inflection points.
- Understanding the difference between relative and absolute extrema.
- The concept of a function's behavior on a closed interval.
Tip: Always check the endpoints of a function on a closed interval because the absolute extrema could occur there, even if there are critical points inside the interval.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Extrema
Critical Points
Function Behavior on a Closed Interval
Formulas
f'(x) = 6x - 12
f(x) = 3x^2 - 12x + 3
Theorems
First Derivative Test
Closed Interval Test
Suitable Grade Level
Grades 11-12
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