Math Problem Statement

Find the critical points and inflection points of f. Then find the intervals of increase and decrease and the intervals of concavity

Find the critical points and inflection points of f. Then find the intervals of increase and decrease and the intervals of concavity.

Solution

To analyze the behavior of f(x)f(x) based on its first and second derivatives (shown in the graph as f(x)f'(x) in pink and f(x)f''(x) in blue), let’s go step-by-step to determine the critical points, inflection points, intervals of increase and decrease, and intervals of concavity.

1. Critical Points

  • Critical points of f(x)f(x) occur where f(x)=0f'(x) = 0 or where f(x)f'(x) is undefined. These points represent possible maxima, minima, or saddle points for f(x)f(x).
  • From the graph, f(x)f'(x) (pink curve) crosses the xx-axis around x=5x = 5, x=12x = 12, and x=19x = 19.
  • Therefore, the critical points for f(x)f(x) are approximately at: x=5,x=12,x=19.x = 5, \quad x = 12, \quad x = 19.

2. Intervals of Increase and Decrease

  • f(x)f(x) is increasing when f(x)>0f'(x) > 0 and decreasing when f(x)<0f'(x) < 0.
  • By observing the pink curve:
    • Increasing Intervals: Between x=5x = 5 and x=12x = 12, and again from x=19x = 19 onwards.
    • Decreasing Intervals: From x=0x = 0 to x=5x = 5, and from x=12x = 12 to x=19x = 19.

3. Inflection Points

  • Inflection points of f(x)f(x) occur where f(x)=0f''(x) = 0 and changes sign, indicating a change in concavity.
  • From the graph, f(x)f''(x) (blue curve) crosses the xx-axis at approximately x=3x = 3, x=9x = 9, x=16x = 16, and x=21x = 21.
  • Thus, the inflection points for f(x)f(x) are approximately at: x=3,x=9,x=16,x=21.x = 3, \quad x = 9, \quad x = 16, \quad x = 21.

4. Intervals of Concavity

  • f(x)f(x) is concave up where f(x)>0f''(x) > 0 and concave down where f(x)<0f''(x) < 0.
  • By observing the blue curve:
    • Concave Up Intervals: From x=3x = 3 to x=9x = 9 and from x=16x = 16 to x=21x = 21.
    • Concave Down Intervals: From x=0x = 0 to x=3x = 3, from x=9x = 9 to x=16x = 16, and from x=21x = 21 onward.

Would you like more detailed explanations on any of these steps, or do you have any questions?


Here are five follow-up questions to deepen your understanding:

  1. How would you classify the critical points (maxima, minima, or saddle points) based on the behavior of f(x)f'(x) and f(x)f''(x)?
  2. Why is it important to check both f(x)f'(x) and f(x)f''(x) for determining intervals of increase, decrease, and concavity?
  3. How can you verify if these inflection points truly indicate a concavity change?
  4. What would the graph of f(x)f(x) itself look like based on this derivative information?
  5. How might the values of f(x)f(x) at the critical points help in sketching the graph of f(x)f(x)?

Tip: To classify critical points more accurately, check if f(x)f''(x) is positive (indicating a local minimum) or negative (indicating a local maximum) at those points.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivative
Critical Points
Inflection Points
Intervals of Increase and Decrease
Intervals of Concavity

Formulas

f'(x) = 0 for critical points
f''(x) = 0 for inflection points

Theorems

First Derivative Test
Second Derivative Test

Suitable Grade Level

Grade 11-12