Math Problem Statement

The coordinates of the endpoints of \( \overline{TU} \) are T(-2, 7) and U(4, -8). Point V is on \( \overline{TU} \) and divides it such that \( TV:UV \) is 1:2. What are the coordinates of V? Write your answers as integers or decimals.

Solution

To solve this problem, we can use the section formula. The section formula helps find the coordinates of a point that divides a line segment in a given ratio.

The coordinates of the endpoints of TU\overline{TU} are:

  • T(2,7)T(-2, 7)
  • U(4,8)U(4, -8)

The ratio TV:UVTV : UV is given as 1:21 : 2, meaning point VV divides the line segment TUTU in the ratio m:n=1:2m:n = 1:2.

The section formula is:

(x,y)=(mx2+nx1m+n,my2+ny1m+n)(x, y) = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right)

Here:

  • x1=2x_1 = -2, y1=7y_1 = 7 (coordinates of TT)
  • x2=4x_2 = 4, y2=8y_2 = -8 (coordinates of UU)
  • m=1m = 1, n=2n = 2

Substituting these values into the formula:

x=14+2(2)1+2=443=0x = \frac{1 \cdot 4 + 2 \cdot (-2)}{1+2} = \frac{4 - 4}{3} = 0 y=1(8)+271+2=8+143=63=2y = \frac{1 \cdot (-8) + 2 \cdot 7}{1+2} = \frac{-8 + 14}{3} = \frac{6}{3} = 2

Thus, the coordinates of VV are (0,2)(0, 2).

Would you like further details on the steps, or do you have any questions?

Here are 5 related questions to expand your understanding:

  1. How would the coordinates of VV change if the ratio were 2:12:1?
  2. What if the point VV divides TUTU externally instead of internally?
  3. Can you apply the section formula in three-dimensional space?
  4. How would you find the length of the segment TVTV?
  5. How does the midpoint formula relate to the section formula?

Tip: The section formula is highly versatile and works for both internal and external divisions, as long as you adjust the sign for external division.

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry

Formulas

Section formula: \( (x, y) = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \)

Theorems

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Suitable Grade Level

Grades 9-12