Math Problem Statement

Use the given sets to find |P∪Q|.

U={a,b,c,d,…,x,y,z}

P={f,i,x,t,u,r,e}

Q={r,e,l,a,x}

Solution

To find PQ|P \cup Q|, which represents the number of unique elements in the union of sets PP and QQ, we’ll go through the following steps:

Step 1: Identify the Elements in Each Set

We have:

  • P={f,i,x,t,u,r,e}P = \{ f, i, x, t, u, r, e \}
  • Q={r,e,l,a,x}Q = \{ r, e, l, a, x \}

Step 2: Form the Union of PP and QQ

The union, PQP \cup Q, includes all unique elements from both PP and QQ.

So, PQ={f,i,x,t,u,r,e,l,a}P \cup Q = \{ f, i, x, t, u, r, e, l, a \}

Step 3: Count the Elements in PQP \cup Q

Counting each unique element:

  • There are 9 elements: f,i,x,t,u,r,e,l,af, i, x, t, u, r, e, l, a.

Conclusion

PQ=9|P \cup Q| = 9

Would you like a breakdown of why duplicates are excluded or more on set operations?

Here are five related questions that expand on this concept:

  1. How would you find the intersection of sets PP and QQ?
  2. If another set S={m,n,o}S = \{m, n, o\} is introduced, how would PQS|P \cup Q \cup S| be calculated?
  3. What is the formula for calculating PQ|P \cup Q| using P|P|, Q|Q|, and PQ|P \cap Q|?
  4. How would you represent PQP \setminus Q, and what does it signify?
  5. How does the concept of complement relate to set union and intersection?

Tip: In set theory, PQ|P \cup Q| counts only unique elements from both sets, effectively ignoring duplicates.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Union of Sets
Cardinality

Formulas

|P ∪ Q| = |P| + |Q| - |P ∩ Q|

Theorems

Union of Sets Cardinality Theorem

Suitable Grade Level

Grades 7-9