Math Problem Statement
find the value of βaβ such that the following system of linear
equations
π + π + ππ = π, π + ππ + π = π, ππ + π β π = π
have
i) exactly one solution
ii) No solution
iii) Infinite number of solutions and find them
put it in matrix and get triangle of zeros
Solution
To solve for the values of such that the system of equations:
x + y + az = 3 \\ x + ay + z = 2 \\ ax + y - z = 1 \end{cases}$$ has: 1. Exactly one solution 2. No solution 3. An infinite number of solutions we can put this system in matrix form and perform row operations to get it into an upper triangular (triangular of zeros) form. ### Step 1: Write the system in matrix form The augmented matrix for the system is: $$\begin{bmatrix} 1 & 1 & a & | & 3 \\ 1 & a & 1 & | & 2 \\ a & 1 & -1 & | & 1 \\ \end{bmatrix}$$ ### Step 2: Perform Gaussian elimination to get upper triangular form We'll aim to make zeros below the main diagonal by performing row operations. #### Row Operations: 1. **Subtract $$\text{Row 1}$$ from $$\text{Row 2}$$:** $$\text{Row 2} = \text{Row 2} - \text{Row 1} \Rightarrow \begin{bmatrix} 1 & 1 & a & | & 3 \\ 0 & a-1 & 1-a & | & -1 \\ a & 1 & -1 & | & 1 \end{bmatrix}$$ 2. **Subtract $$a \times \text{Row 1}$$ from $$\text{Row 3}$$:** $$\text{Row 3} = \text{Row 3} - a \times \text{Row 1} \Rightarrow \begin{bmatrix} 1 & 1 & a & | & 3 \\ 0 & a-1 & 1-a & | & -1 \\ 0 & 1-a & -1-a^2 & | & 1 - 3a \end{bmatrix}$$ 3. **Next, eliminate the second element in the third row by using $$\text{Row 2}$$:** Subtract $$\frac{1-a}{a-1} \times \text{Row 2}$$ from $$\text{Row 3}$$: (Continue until upper triangular form is reached.)Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Linear Algebra
Systems of Equations
Gaussian Elimination
Formulas
Ax = b
Row reduction to echelon form
Theorems
Existence and uniqueness theorem for linear systems
Suitable Grade Level
Grades 10-12
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