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For the circuit below: Is = 5 A, Vs = 10 V, and R = 3 Ohms.  Find the voltage, vr, in Volts.

Note: The head of the arrow denotes the + node of the voltage.

To solve for the voltage \( v_R \) across the resistor \( R \), we can use Ohm's Law, which is defined as:

\[
v_R = I_s \cdot R
\]

Where:
- \( I_s = 5 \, \text{A} \) (the current through the circuit)
- \( R = 3 \, \Omega \) (the resistance)

Let's calculate \( v_R \):

\[
v_R = 5 \, \text{A} \times 3 \, \Omega = 15 \, \text{V}
\]

Since the arrow in the diagram indicates the positive direction of the voltage across the resistor, the voltage \( v_R \) is 15 V in the direction of the arrow shown.

### Summary:
- \( v_R = 15 \, \text{V} \)

Would you like to explore more details or ask additional questions?

Here are some follow-up questions:
1. What would the current \( I_s \) be if the resistance \( R \) is doubled?
2. How would the voltage \( v_R \) change if the voltage source \( V_s \) were increased to 20 V?
3. Can you describe the power dissipated by the resistor in this circuit?
4. What would happen to the circuit if the resistor were replaced with a short circuit (i.e., \( R = 0 \))?
5. How does the voltage across the resistor relate to the voltage source in a series circuit?

**Tip:** When analyzing circuits, always check the direction of current and polarity of voltage to ensure you apply the correct signs in your calculations.

For the circuit below: Is = 5 A, Vs = 10 V, and R = 3 Ohms. Find the voltage, vr, in Volts. Note: The head of the arrow denotes the + node of the voltage.

Solve for the voltage across a resistor in a simple circuit where Is = 5 A, Vs = 10 V, and R = 3 Ohms. Using Ohm's Law, we calculate the voltage vR to be 15 V. Suitable for Grades 9-12.

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