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The given function is in vertex form, which is:

\[
f(x) = a(x-h)^2 + k
\]

Here, \( (h, k) \) represents the vertex of the parabola. In your function:

\[
f(x) = 8(x - 7)^2 - 1
\]

- \( h = 7 \) (since \( x - 7 \), the \( h \) is 7)
- \( k = -1 \) (the constant outside the squared term is -1)

Therefore, the vertex is:

\[
(7, -1)
\]

Would you like further details or explanations?

### Related Questions:
1. What does the value of "a" (in this case 8) tell us about the graph of the parabola?
2. How would you find the axis of symmetry from this equation?
3. How does shifting the function horizontally affect the graph?
4. How does the constant \( k \) affect the position of the vertex?
5. What is the direction of the parabola’s opening?

**Tip:** The vertex form of a quadratic function makes it very easy to find the vertex directly from the equation.

Find the vertex of the function f(x) = 8(x - 7)^2 - 1

This lesson explains how to find the vertex of the quadratic function f(x) = 8(x - 7)^2 - 1 using the vertex form. The solution is suitable for students in Grades 8-10 and includes key concepts in quadratic functions.

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