The image you've provided shows a rhombus $PQRS$ with the following information given:

• Side $PS = x$
• Side $PR = x$
• Diagonal $SQ = 3x - 7$
• Diagonal $OR = 2x - 3$

In a rhombus, the diagonals bisect each other at right angles and are equal in length, but they are not equal to each other. However, all four sides of a rhombus are equal in length.

Since $PS = PR$, and both of these are equal to the sides $PQ$ and $QR$, we can set up an equation using the property that the diagonals bisect each other.

Given that the diagonals of a rhombus are equal, the equation to find $x$ will be:

$3x - 7 = 2x - 3$

Let's solve for $x$:

$3x - 7 = 2x - 3$

Subtract $2x$ from both sides:

$x - 7 = -3$

Add 7 to both sides:

$x = 4$

So, the value of $x$ is $\boxed{4}$.

Would you like more details, or do you have any questions?

Here are five related questions:

1. How do we verify that all sides of a rhombus are equal after finding $x$?
2. What is the relationship between the diagonals in a rhombus?
3. How would the problem change if the figure was a square instead of a rhombus?
4. Can you find the lengths of the diagonals after determining $x$?
5. What would be the area of the rhombus using the given diagonal lengths?

Tip: Always check if the diagonals bisect each other at right angles when solving problems involving rhombuses.