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The function provided is \( f(x) = 3x^2 - 6 \).

We are asked to find \( f(-3) \). To do so, substitute \( x = -3 \) into the function:

\[
f(-3) = 3(-3)^2 - 6
\]
First, calculate \( (-3)^2 \):
\[
(-3)^2 = 9
\]
Now, substitute this value back into the equation:
\[
f(-3) = 3(9) - 6 = 27 - 6 = 21
\]

So, the value of \( f(-3) \) is 21.

Do you need further details or explanations?

Here are 5 related questions for practice:
1. What is the value of \( f(0) \) for the same function \( f(x) = 3x^2 - 6 \)?
2. What is the value of \( f(2) \) for \( f(x) = 3x^2 - 6 \)?
3. How does the function behave as \( x \to \infty \)?
4. How can you find the roots of \( f(x) = 0 \)?
5. What is the minimum value of \( f(x) \) for this quadratic function?

**Tip:** When dealing with quadratic functions, always remember that their graph is a parabola. If the coefficient of \( x^2 \) is positive, the parabola opens upwards!

If f(x) = 3x^2 - 6, find the value of f(-3).

Learn how to find the value of f(-3) when f(x) = 3x^2 - 6. Follow the step-by-step substitution process to calculate the correct answer. Suitable for students in Grades 9-10.

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