Math Problem Statement

We'll be analyzing the surface area of a round cylinder. Given that the height of the cylinder is 6 inches, what is the radius of the cylinder if the surface area is 175 square inches?

Solution

The image contains a math problem about analyzing the surface area of a round cylinder, specifically focusing on deriving an expression for the radius rr in terms of the surface area AA.

Here is a step-by-step breakdown of the problem:

Given:

  • The height of the cylinder is fixed at 6 inches.
  • The surface area AA of the cylinder is expressed as: A=2πr2+12πrA = 2\pi r^2 + 12\pi r where rr is the radius of the base of the cylinder.

Part a:

You're asked to determine the domain of the surface area function, A(r)=2πr2+12πrA(r) = 2\pi r^2 + 12\pi r, which describes how the surface area changes as a function of the radius.

Domain of A(r)A(r):

For a physical cylinder, the radius rr must be non-negative. Therefore, the domain is: r0r \geq 0 However, in practical terms, r>0r > 0, since a radius of zero would imply no cylinder exists.

Part b:

Here, you are asked to solve for the radius rr as a function of AA, meaning you need to find the inverse of the function A(r)A(r).

The given equation is quadratic in terms of rr: A=2πr2+12πrA = 2\pi r^2 + 12\pi r To solve for rr, follow these steps:

  1. Divide both sides by 2π2\pi: A2π=r2+6r\frac{A}{2\pi} = r^2 + 6r

  2. Rearrange into standard quadratic form: r2+6rA2π=0r^2 + 6r - \frac{A}{2\pi} = 0

  3. Solve using the quadratic formula: r=6±624(1)(A2π)2(1)r = \frac{-6 \pm \sqrt{6^2 - 4(1)(-\frac{A}{2\pi})}}{2(1)} Simplifying further: r=6±36+2A/π2r = \frac{-6 \pm \sqrt{36 + 2A/\pi}}{2} Taking only the positive root (since radius must be positive): r=6+36+2A/π2r = \frac{-6 + \sqrt{36 + 2A/\pi}}{2} r(A)=3+36+2A/π2r(A) = -3 + \frac{\sqrt{36 + 2A/\pi}}{2}

Part c:

This part involves finding the radius rr when the surface area AA is 175 square inches. Using the inverse function derived in part b:

  1. Substitute A=175A = 175 into the formula: r=6+36+2(175)π2r = \frac{-6 + \sqrt{36 + \frac{2(175)}{\pi}}}{2} We can now calculate this numerically.

Let me compute this for you.The radius rr of the cylinder, when the surface area is 175 square inches, is approximately 3.07 inches.

Would you like further details on any part of the solution or explanation?

Here are some related questions for practice:

  1. What happens to the surface area as the radius increases?
  2. How does changing the height affect the surface area formula?
  3. Can you derive the volume of the cylinder in terms of rr?
  4. What would the domain of the inverse function r(A)r(A) be?
  5. How would you solve this problem if the surface area were given in a different unit, such as square centimeters?

Tip: Always check the units when solving geometric problems to ensure the final answer is consistent with the given data.

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Math Problem Analysis

Mathematical Concepts

Surface Area of a Cylinder
Algebra
Quadratic Equations

Formulas

Surface Area of Cylinder A = 2πr^2 + 2πrh
Quadratic equation formula: r = (-b ± √(b² - 4ac)) / 2a

Theorems

Quadratic Formula

Suitable Grade Level

Grades 9-12