Math Problem Statement
show work for each step
Solution
We are tasked with finding the point(s) on the graph of the function where the function has a horizontal tangent line.
Step 1: Understand the problem
- A horizontal tangent line occurs when the slope of the tangent line is zero.
- The slope of the tangent line is given by the derivative of the function .
Step 2: Find the derivative of
We differentiate with respect to :
Using basic differentiation rules:
Step 3: Set the derivative equal to zero
To find the points where the tangent line is horizontal, we need to set the derivative equal to zero and solve for :
Step 4: Solve for
Simplify and solve the equation:
So, the function has horizontal tangent lines at and .
Step 5: Find the corresponding -values
To find the points, we substitute and into the original function :
-
For :
-
For :
Step 6: Conclusion
The points on the graph where the function has horizontal tangent lines are:
Would you like any additional details or clarifications?
Here are 5 related questions to deepen your understanding:
- What is the geometric meaning of a horizontal tangent line in terms of the graph's shape?
- How do we determine whether the horizontal tangent line corresponds to a local maximum or minimum?
- How does the second derivative of a function help classify critical points (such as those with horizontal tangents)?
- Can a cubic function have more than two points with horizontal tangent lines?
- How would the function's behavior change if we altered the constants in ?
Tip: When solving for critical points, always check the second derivative to classify the nature of the critical points (whether they are maxima, minima, or points of inflection).
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Math Problem Analysis
Mathematical Concepts
Differentiation
Critical Points
Algebra
Formulas
f'(x) = 3x^2 - 12
Set f'(x) = 0 to find critical points
Theorems
First Derivative Test
Suitable Grade Level
Grades 10-12