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The problem asks for the perimeter of the parallelogram, which is given with side lengths of 17 cm and 12 cm.

The formula for the perimeter \( P \) of a parallelogram is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Here:
- The length is \( 17 \, \text{cm} \)
- The width is \( 12 \, \text{cm} \)

So, substituting the values:
\[
P = 2 \times (17 + 12) = 2 \times 29 = 58 \, \text{cm}
\]

Thus, the perimeter is **58 cm**.

Would you like more details or have any questions? Here are some related questions for further exploration:

1. How would the formula change if the shape were a rectangle instead of a parallelogram?
2. How do you calculate the area of a parallelogram with the given side lengths?
3. What is the difference between a rhombus and a parallelogram in terms of perimeter?
4. If one side of the parallelogram increased by 5 cm, how would that affect the perimeter?
5. How can you find the perimeter if only the diagonals of a parallelogram are given?

**Tip**: The perimeter of a parallelogram only depends on the lengths of its sides, not the angles or diagonals.

Find the perimeter of the parallelogram. The parallelogram has side lengths of 17 cm and 12 cm.

Learn how to calculate the perimeter of a parallelogram with side lengths of 17 cm and 12 cm using the formula P = 2 × (length + width). Suitable for students in Grades 5-7.

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