To find the missing angle $x$ in a triangle, we use the property that the sum of the angles in a triangle is always $180^\circ$.

From the image:

• The first angle is $45^\circ$,
• The second angle is $97^\circ$,
• The third angle $x$ is unknown.

The equation becomes: $45^\circ + 97^\circ + x = 180^\circ$

Simplify: $142^\circ + x = 180^\circ$

Solve for $x$: $x = 180^\circ - 142^\circ$ $x = 38^\circ$

Final Answer:

$x = 38^\circ$

Would you like additional details or a breakdown of how to approach similar problems?

Here are 5 related questions for further practice:

1. What is the missing angle if the other two angles are $60^\circ$ and $70^\circ$?
2. How do you classify a triangle based on its angles (e.g., acute, obtuse)?
3. Can the sum of any two angles in a triangle exceed $180^\circ$? Why or why not?
4. How do you calculate the angles in an isosceles triangle if one angle is given?
5. What is the sum of angles in a quadrilateral?

Tip: Always verify your work by ensuring the sum of all angles equals $180^\circ$ in a triangle.