Find the mean, median, and mode for each data set.
a) 12, 16, 11, 15, 21, 13, 17, 17, 15, 24, 20, 16
b) 15.2, 15.8, 15.9, 15.3, 14.8, 13.7, 15.9, 14.5, 14.6, 15.8
c) 0.034, 0.045, 0.043, 0.037, 0.036, 0.041, 0.040
d) 15, 17, 17, 17, 18, 19, 25, 37, 37, 42, 50, 61, 70, 85

Here are the calculated mean, median, and mode for each data set:

a) \( 12, 16, 11, 15, 21, 13, 17, 17, 15, 24, 20, 16 \)
- Mean: \( 16.42 \)
- Median: \( 16.0 \)
- Mode: \( 15 \)

b) \( 15.2, 15.8, 15.9, 15.3, 14.8, 13.7, 15.9, 14.5, 14.6, 15.8 \)
- Mean: \( 15.15 \)
- Median: \( 15.25 \)
- Mode: \( 15.8 \)

c) \( 0.034, 0.045, 0.043, 0.037, 0.036, 0.041, 0.040 \)
- Mean: \( 0.0394 \)
- Median: \( 0.04 \)
- Mode: \( 0.034 \)

d) \( 15, 17, 17, 17, 18, 19, 25, 37, 37, 42, 50, 61, 70, 85 \)
- Mean: \( 36.43 \)
- Median: \( 31.0 \)
- Mode: \( 17 \)

Would you like further details on any of the calculations?

Here are 5 related questions to expand your understanding:
1. How does the mode differ from the median in these data sets?
2. How can you interpret the median when the data set is skewed?
3. What is the significance of having multiple modes in a data set?
4. Why is the mean more sensitive to outliers compared to the median?
5. How would you handle a situation where there is no mode in the data?

**Tip:** The median is often used when the data contains outliers, as it provides a better measure of central tendency in such cases.

Calculate the mean, median, and mode for data sets: a) 12, 16, 11, 15, 21, 13, 17, 17, 15, 24, 20, 16; b) 15.2, 15.8, 15.9, 15.3, 14.8, 13.7, 15.9, 14.5, 14.6, 15.8; c) 0.034, 0.045, 0.043, 0.037, 0.036, 0.041, 0.040; d) 15, 17, 17, 17, 18, 19, 25, 37, 37, 42, 50, 61, 70, 85. Understand how to compute these statistical measures and interpret their significance in different data sets.

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