The expression provided is:

$2x^2 - 4 + 5$

First, simplify the expression:

$2x^2 - 4 + 5 = 2x^2 + 1$

Now, find the limit as $x$ approaches $-3$:

$\lim_{x \to -3} \left( 2x^2 + 1 \right)$

Substitute $x = -3$ into the expression:

$2(-3)^2 + 1 = 2(9) + 1 = 18 + 1 = 19$

Therefore, the limit is:

$\boxed{19}$

Would you like further details or have any questions?

Here are 5 related questions:

1. What is the limit of $x^2 - 3x + 2$ as $x$ approaches 2?
2. How do you find the limit of a polynomial function as $x$ approaches a given value?
3. Can the limit of a function be different from the function's value at that point?
4. What happens to the limit if you approach $-3$ from the right or left side?
5. How would the limit change if the expression had been $2x^2 - 4x + 5$?

Tip: When finding the limit of a polynomial, directly substitute the value into the polynomial if the function is continuous.