Math Problem Statement

Given right triangle A, B, CABC with altitude start overline, B, D, end overlineBD drawn to hypotenuse start overline, A, C, end overlineAC. If A, D, equals, 7AD=7 and B, D, equals, 14, commaBD=14, what is the length of start overline, D, C, end overline, question markDC?

Solution

We are given a right triangle ABC\triangle ABC with altitude BDBD drawn to the hypotenuse ACAC. The following lengths are given:

  • AD=7AD = 7,
  • BD=14BD = 14,
    and we need to find DCDC.

Steps to Solve:

  1. The Altitude Rule in a Right Triangle
    The altitude BDBD divides the hypotenuse ACAC into two segments, ADAD and DCDC. The geometric mean property of a right triangle states:
    BD2=ADDCBD^2 = AD \cdot DC Substituting the given values: 142=7DC14^2 = 7 \cdot DC

  2. Simplify the Equation
    Calculate 14214^2: 196=7DC196 = 7 \cdot DC

  3. Solve for DCDC:
    Divide both sides by 7: DC=1967=28DC = \frac{196}{7} = 28

Final Answer:

The length of DCDC is: 28\boxed{28}


Do you want a detailed geometric explanation or a diagram?
Here are 5 related questions to deepen understanding:

  1. How can we verify the altitude rule using similar triangles?
  2. What is the length of the hypotenuse ACAC?
  3. Can you explain the geometric mean property in detail?
  4. What is the area of ABC\triangle ABC?
  5. How does the Pythagorean theorem relate to this setup?

Tip: Always look for relationships between segments in right triangles, as similar triangles often simplify problems.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Geometric Mean Property

Formulas

BD^2 = AD × DC

Theorems

Geometric Mean Theorem
Properties of Similar Triangles

Suitable Grade Level

Grades 8-10