Math Problem Statement

find leg 1 and leg 2 with the distance as well

Solution

To find the legs and hypotenuse of the right triangle formed by the points (7,4)(-7, 4) and (4,1)(-4, -1), we can follow these steps:

  1. Leg 1 (Horizontal Distance): The horizontal distance is the difference in the x-coordinates of the two points. This forms one leg of the right triangle. Leg 1=x2x1=4(7)=4+7=3\text{Leg 1} = |x_2 - x_1| = |-4 - (-7)| = |-4 + 7| = 3

  2. Leg 2 (Vertical Distance): The vertical distance is the difference in the y-coordinates of the two points. This forms the other leg of the right triangle. Leg 2=y2y1=14=5=5\text{Leg 2} = |y_2 - y_1| = |-1 - 4| = |-5| = 5

  3. Hypotenuse (Distance between the two points): The hypotenuse is the distance between the two points, which can be found using the Pythagorean theorem: d=(Leg 1)2+(Leg 2)2=32+52=9+25=345.83d = \sqrt{(\text{Leg 1})^2 + (\text{Leg 2})^2} = \sqrt{3^2 + 5^2} = \sqrt{9 + 25} = \sqrt{34} \approx 5.83

Thus, the two legs of the triangle are 3 and 5, and the distance (hypotenuse) is approximately 5.83 units.

Would you like further clarification or additional details?

Here are some related questions:

  1. How can we determine the midpoint of a line segment between two points?
  2. What is the formula for finding the slope of a line given two points?
  3. How do you use the distance formula in 3D geometry?
  4. What are the properties of a right triangle in terms of angles?
  5. How can you calculate the area of a triangle given its base and height?

Tip: Always visualize the points on a graph if possible. This can help you better understand the geometry and distances involved.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Distance Formula
Pythagorean Theorem

Formulas

Distance formula
Pythagorean theorem

Theorems

Pythagorean theorem

Suitable Grade Level

Grades 7-9