The equation of the line is:

$9y - x = -1$

To find the x-intercept and y-intercept, we proceed as follows:

1. Find the x-intercept:

The x-intercept occurs when $y = 0$. Substitute $y = 0$ into the equation:

$9(0) - x = -1$

$-x = -1 \quad \implies \quad x = 1$

So, the x-intercept is:

$(1, 0)$

2. Find the y-intercept:

The y-intercept occurs when $x = 0$. Substitute $x = 0$ into the equation:

$9y - 0 = -1$

$9y = -1 \quad \implies \quad y = -\frac{1}{9}$

So, the y-intercept is:

$\left( 0, -\frac{1}{9} \right)$

Final Answer:

• x-intercept: $(1, 0)$
• y-intercept: $\left( 0, -\frac{1}{9} \right)$

Would you like me to explain the steps in greater detail or assist further? 😊

Related Questions:

1. How do you find intercepts for a line in general form $Ax + By = C$?
2. Can you graph the line $9y - x = -1$ based on these intercepts?
3. How do you convert $9y - x = -1$ into slope-intercept form $y = mx + b$?
4. What is the slope of the line $9y - x = -1$?
5. How do intercepts help in graphing linear equations?

Tip:

Always remember that the x-intercept is found by setting $y = 0$, and the y-intercept is found by setting $x = 0$.