Math Problem Statement
Solution
Let's solve this!
We are given the second derivative of a function as:
We need to find the x-coordinates of the inflection points. Inflection points occur where the second derivative changes sign.
Steps to Solve:
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Identify Critical Points: Set .
This equation is satisfied if any of the following factors is zero:So, the possible inflection points are at , , and .
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Check Sign Changes around Critical Points: To confirm if these are actual inflection points, we need to see if changes sign at these points. We analyze the sign of on the intervals determined by , , and .
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Interval:
Pick :
(positive) -
Interval:
Pick :
(positive) -
Interval:
Pick :
(positive) -
Interval:
Pick :
(positive)
-
Conclusion:
- There is no sign change around any of the points , , or .
- Therefore, there are no inflection points.
Answer:
The correct option is:
(A) none
Would you like further clarifications or additional practice problems?
Related Questions:
- How do you find inflection points for functions involving trigonometric terms?
- What’s the difference between critical points and inflection points?
- Can inflection points occur where the second derivative is undefined?
- What happens to the concavity of a function at an inflection point?
- How does the second derivative test relate to finding maxima or minima?
Tip: When dealing with high powers like , always check sign changes to confirm inflection points.
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Math Problem Analysis
Mathematical Concepts
Calculus
Second Derivative
Inflection Points
Sign Changes
Formulas
f''(x) = 0 to find critical points
Sign analysis to confirm inflection points
Theorems
Inflection point occurs where second derivative changes sign
Suitable Grade Level
Grades 11-12 or introductory college calculus
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