To find $g(x+5)$ when $g(x) = x^2 - 2x$, follow these steps:

1. Substitute $x+5$ into the function $g(x)$: $g(x+5) = (x+5)^2 - 2(x+5)$

2. Expand the squared term: $(x+5)^2 = x^2 + 10x + 25$ So, $g(x+5) = x^2 + 10x + 25 - 2(x+5)$

3. Distribute and simplify: $g(x+5) = x^2 + 10x + 25 - 2x - 10$

4. Combine like terms: $g(x+5) = x^2 + 8x + 15$

So, $g(x+5) = x^2 + 8x + 15$.

Would you like more details or have any questions?

Here are some related questions you might find interesting:

1. What is $g(x-3)$ if $g(x) = x^2 - 2x$?
2. How do you find the vertex of the quadratic function $g(x) = x^2 - 2x$?
3. How does shifting the graph horizontally affect the equation of $g(x)$?
4. What is the axis of symmetry for the function $g(x) = x^2 - 2x$?
5. Can you factorize $g(x) = x^2 - 2x$?

Tip: When dealing with functions, substituting values (like $x+5$) can shift the graph horizontally.