Math Problem Statement
Solution
Let's break down the problem and solve the questions based on the provided graph and functions:
Given Functions:
Part (a): Find and
Step 1: Calculate
We substitute into the equation for :
So, .
Step 2: Calculate
We substitute into the equation for :
So, .
Part (b): Can you find ?
To calculate , substitute into the equation:
Since the square root of a negative number is not a real number, is undefined in the real number system.
Part (c): Find the domain of , , and
Domain of
The function is a linear function, which is defined for all real numbers. So, the domain of is:
Domain of
For the square root function , the argument inside the square root must be non-negative: So, the domain of is:
Domain of
Since , the domain of is the intersection of the domains of and . Since is defined for all , the domain of is the same as the domain of :
Summary of Results:
- is undefined.
- Domain of :
- Domain of :
- Domain of :
Would you like further clarification on any part? Here are some related questions to consider:
- What happens if you add another function to ?
- Can you find for ?
- What is the range of ?
- Can and intersect, and if so, where?
- How would you solve ?
Tip: Always check the domain of each function when combining them to avoid undefined expressions.
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Math Problem Analysis
Mathematical Concepts
Functions
Algebra
Square Roots
Domains
Formulas
f(x) = x + 1
g(x) = sqrt(x + 3)
(f + g)(x) = f(x) + g(x) = x + 1 + sqrt(x + 3)
Theorems
Properties of square roots
Function domain intersection
Suitable Grade Level
Grades 9-11
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