Given the function $f(x) = 2x - 4$, we need to find $f\left( \frac{4}{3} \right)$.

To do this, substitute $x = \frac{4}{3}$ into the function:

$f\left( \frac{4}{3} \right) = 2\left( \frac{4}{3} \right) - 4$

$= \frac{8}{3} - 4$

Convert 4 into a fraction with denominator 3:

$= \frac{8}{3} - \frac{12}{3}$

Now subtract:

$= \frac{8 - 12}{3} = \frac{-4}{3}$

Thus, $f\left( \frac{4}{3} \right) = \frac{-4}{3}$.

Would you like more details or have any questions?

Here are 5 related questions:

1. What is the slope of the linear function $f(x) = 2x - 4$?
2. How would you find the x-intercept of the function $f(x) = 2x - 4$?
3. What is $f(0)$ for the function $f(x) = 2x - 4$?
4. If $f(x) = 2x - 4$, for which value of $x$ does $f(x) = 0$?
5. How do you graph the function $f(x) = 2x - 4$?

Tip: For linear functions like $f(x) = 2x - 4$, the slope is constant and gives the rate of change.