Math Problem Statement

Find the domain of the function f\left(x\right)=\frac{1}{3x+8}

. What is the only value of not in the domain?

Only Value

Solution

To find the domain of the function f(x)=13x+8f(x) = \frac{1}{3x + 8}, we need to identify the values of xx for which the function is undefined. The function will be undefined when the denominator equals zero because division by zero is not possible.

Step 1: Find the value where the denominator is zero

Set the denominator equal to zero and solve for xx: 3x+8=03x + 8 = 0

Step 2: Solve for xx

3x=83x = -8 x=83x = -\frac{8}{3}

Step 3: Determine the domain

The function is defined for all real values of xx except x=83x = -\frac{8}{3}.

Final Answer:

The only value not in the domain is x=83x = -\frac{8}{3}.

Would you like to see more details or have any questions?

Here are 5 related questions that expand on this topic:

  1. How do you find the domain of functions with square roots?
  2. What is the domain of the function g(x)=3x+8g(x) = \sqrt{3x+8}?
  3. How does the domain change for functions like f(x)=1(3x+8)2f(x) = \frac{1}{(3x+8)^2}?
  4. What happens to the domain if the function is f(x)=ln(3x+8)f(x) = \ln(3x+8)?
  5. How do you determine the range of the function f(x)=13x+8f(x) = \frac{1}{3x+8}?

Tip: When finding the domain of rational functions, always start by identifying values that make the denominator zero, as these are the points where the function is undefined.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Domain and Range

Formulas

f(x) = 1/(3x + 8)

Theorems

Division by zero

Suitable Grade Level

Grades 9-10