Find the difference bet.                                         3y^ + -2y

The expression you've provided seems to be \( 3y^2 \) and \(-2y\). It looks like you're asking for the difference between these two terms. The difference is calculated as:

\[
3y^2 - (-2y)
\]

Subtracting a negative is the same as adding the positive, so:

\[
3y^2 + 2y
\]

So, the difference between the two terms is \( 3y^2 + 2y \).

Would you like further details or have any questions?

Here are some related questions you might find interesting:
1. What is the sum of \(3y^2\) and \(-2y\)?
2. How do you factor the expression \(3y^2 + 2y\)?
3. What is the derivative of \(3y^2 + 2y\) with respect to \(y\)?
4. How do you solve the equation \(3y^2 + 2y = 0\)?
5. What happens if you subtract \(3y^2\) from \(2y\)?

**Tip:** When subtracting negative numbers, remember to change the sign and add the numbers instead.

Learn how to find the difference between algebraic terms 3y^2 and -2y. Understand the process of subtracting algebraic expressions, including handling negative signs and adding the positive. Suitable for students in Grades 7-9.

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