To find the correlation coefficient $r$ for this data set, we can use the fact that the correlation coefficient $r$ is related to the coefficient of determination $r^2$ by the equation:

$r = \pm \sqrt{r^2}$

In the provided image, $r^2 = 0.1681$. Therefore, we take the square root of $0.1681$ to calculate $r$.

Let me do that now.The correlation coefficient $r$ for this data set is approximately $0.41$.

Would you like more details on this calculation or how it relates to the data set?

Here are 5 related questions:

1. What is the significance of the sign of $r$ (positive or negative)?
2. How does the value of $r^2$ compare to $r$ in terms of interpretation?
3. How would you interpret an $r$ value of 0.41 in terms of strength of correlation?
4. How do you plot a trendline in Excel to find $r^2$?
5. What would happen to $r$ if $r^2$ were closer to 1?

Tip: The closer $r^2$ is to 1, the stronger the linear relationship between the variables.