To find the coefficients \(a\), \(b\), and \(c\) for the quadratic equation \(2x^2 - 21x - 36\), you can compare it to the general form of a quadratic equation:

\[
ax^2 + bx + c = 0
\]

In this case:
- \(a\) is the coefficient of \(x^2\),
- \(b\) is the coefficient of \(x\),
- \(c\) is the constant term.

By comparing:

\[
2x^2 - 21x - 36
\]

We get:
- \(a = 2\)
- \(b = -21\)
- \(c = -36\)

These are the values of \(a\), \(b\), and \(c\) for the given quadratic equation.

Would you like to see the detailed process of solving this quadratic equation or have any questions about it?

Here are 5 related questions:
1. How do you solve the quadratic equation \(2x^2 - 21x - 36 = 0\) using the quadratic formula?
2. What is the vertex form of the quadratic equation \(2x^2 - 21x - 36\)?
3. How do you factorize the quadratic equation \(2x^2 - 21x - 36\)?
4. What are the roots of the quadratic equation \(2x^2 - 21x - 36 = 0\)?
5. How does the discriminant determine the nature of the roots for \(2x^2 - 21x - 36\)?

**Tip:** When solving quadratic equations, always check if it can be factored easily before using the quadratic formula. This can save time and simplify calculations.

Learn how to find coefficients a, b, c for the quadratic equation 2x^2 - 21x - 36 with a detailed step-by-step solution. This problem covers key algebraic concepts, including the quadratic equation formula and the quadratic formula theorem. Suitable for students in Grades 7-9.

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