Math Problem Statement

Two parallel lines are cut by a transversal. Suppose m∠3 = 102°. Find m∠5 and m∠8.

Solution

To solve this problem, let's analyze the angles formed by the parallel lines and the transversal:

  1. We are given that m3=102m \angle 3 = 102^\circ.

  2. Since angles 3 and 5 are corresponding angles (formed by the transversal crossing the parallel lines), they are equal. Therefore: m5=102m \angle 5 = 102^\circ

  3. Similarly, angles 3 and 8 are alternate exterior angles. For two parallel lines cut by a transversal, alternate exterior angles are also equal. Thus: m8=102m \angle 8 = 102^\circ

Solution Summary:

  • m5=102m \angle 5 = 102^\circ
  • m8=102m \angle 8 = 102^\circ

Would you like further clarification on any of these steps?


Here are 5 related questions that expand on this information:

  1. What are the properties of corresponding angles when two parallel lines are cut by a transversal?
  2. How can you determine the measure of angle 1 in this diagram?
  3. If m4m \angle 4 was given, how could you find m7m \angle 7?
  4. What are alternate interior angles, and which angles in this diagram are alternate interior angles?
  5. How would the solution change if the lines were not parallel?

Tip: Remember that corresponding and alternate angles are only equal when the lines involved are parallel.

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Math Problem Analysis

Mathematical Concepts

Parallel lines
Transversals
Angle relationships
Corresponding angles
Alternate exterior angles

Formulas

Corresponding angles are equal
Alternate exterior angles are equal

Theorems

Parallel Lines Theorem
Corresponding Angles Postulate
Alternate Exterior Angles Theorem

Suitable Grade Level

Grades 8-10