ABCD is a parallelogram in which angle A =95 find angle B and angle c

In a parallelogram, opposite angles are equal, and adjacent angles are supplementary (they add up to \(180^\circ\)).

Given:
- \(\angle A = 95^\circ\)
- Since \(\angle A\) and \(\angle B\) are adjacent, they must add up to \(180^\circ\).

Thus:
\[
\angle B = 180^\circ - \angle A = 180^\circ - 95^\circ = 85^\circ
\]

Now, \(\angle C\) is opposite to \(\angle A\), so:
\[
\angle C = \angle A = 95^\circ
\]

And \(\angle D\) is opposite to \(\angle B\), so:
\[
\angle D = \angle B = 85^\circ
\]

Therefore, the angles are:
- \(\angle A = 95^\circ\)
- \(\angle B = 85^\circ\)
- \(\angle C = 95^\circ\)
- \(\angle D = 85^\circ\)

Would you like further details or clarifications?

Here are some related questions to consider:
1. What are the properties of a parallelogram in terms of angles and sides?
2. How would the angle values change if \(\angle A\) were \(75^\circ\)?
3. Can a parallelogram have right angles? If yes, what shape would that be?
4. How would you calculate the angles in a parallelogram if only two angles were given?
5. What is the relationship between the diagonals in a parallelogram?

**Tip:** In any parallelogram, adjacent angles are always supplementary!

ABCD is a parallelogram in which angle A = 95°. Find angle B and angle C.

Learn how to calculate the unknown angles in a parallelogram where angle A is 95°. This problem involves key geometry concepts like the properties of parallelograms and supplementary angles. Suitable for students in Grades 6-8.

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