Math Problem Statement

a) Write the value of sin(θ) for the right-angled triangle below as a fraction. b) Using your answer to part a), work out the size of angle θ. Give your answer in degrees to 1 d.p.

Solution

Let's break down the problem from the image:

Part (a): Write the value of sinθ\sin \theta as a fraction

For a right-angled triangle: sinθ=opposite sidehypotenuse\sin \theta = \frac{\text{opposite side}}{\text{hypotenuse}} From the diagram:

  • Opposite side to θ\theta = 13 cm
  • Hypotenuse = 18 cm

So: sinθ=1318\sin \theta = \frac{13}{18}


Part (b): Calculate the size of angle θ\theta (in degrees, 1 decimal place)

We need to find the angle θ\theta using: sinθ=1318\sin \theta = \frac{13}{18}

To find θ\theta, take the inverse sine (arcsin) of the fraction: θ=sin1(1318)\theta = \sin^{-1}\left(\frac{13}{18}\right)

Using a calculator: θsin1(0.7222)46.0\theta \approx \sin^{-1}(0.7222) \approx 46.0^\circ


Final Answers:

  • (a) sinθ=1318\sin \theta = \frac{13}{18}
  • (b) θ46.0\theta \approx 46.0^\circ (to 1 decimal place)

Would you like me to explain any of the steps in more detail or check further calculations?

Here are 5 related questions to deepen your understanding:

  1. What are the other trigonometric ratios for this triangle (cosine and tangent)?
  2. How can we use the Pythagorean theorem to verify the hypotenuse length?
  3. What is the meaning of the inverse sine function?
  4. What happens if you use radians instead of degrees to calculate the angle?
  5. Can you convert the sine value into a decimal and still maintain accuracy?

Tip: In trigonometry, it's good practice to always label the sides relative to the angle of interest (opposite, adjacent, hypotenuse).

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right-Angled Triangles
Sine Function
Inverse Trigonometric Functions

Formulas

sin(θ) = opposite / hypotenuse
θ = sin^(-1)(opposite / hypotenuse)

Theorems

Trigonometric Ratios in Right Triangles

Suitable Grade Level

Grades 9-11