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In the given parallelogram \( ABCD \), we are tasked with finding \( \angle CFG \).

### Steps to Solve:
1. **Identify the angles in the diagram**:
   - \( \angle AEB = 65^\circ \)
   - \( \angle CFE = 18^\circ \)
   - \( ABCD \) is a parallelogram, which implies opposite sides are parallel, and the corresponding angles are equal.

2. **Using angle relationships**:
   - Since \( ABCD \) is a parallelogram, \( AB \parallel DC \) and \( EF \) is a transversal. Therefore, \( \angle EAB \) (or \( \angle AEB \)) is supplementary to \( \angle CFG \), because they are on the same side of the transversal \( EF \).
   - Supplementary angles sum to \( 180^\circ \), so:
     \[
     \angle CFG = 180^\circ - \angle AEB = 180^\circ - 65^\circ = 115^\circ
     \]

Thus, \( \angle CFG = 115^\circ \).

Would you like more details or have any further questions?

### Related questions:
1. What are the properties of a parallelogram in terms of angles and sides?
2. How do transversal lines affect angles in parallel line systems?
3. Can you explain the concept of supplementary angles?
4. What is the relationship between alternate interior angles in parallelograms?
5. How do you calculate unknown angles using given angles and geometric properties?

**Tip**: In a parallelogram, opposite angles are always equal, and adjacent angles are supplementary (add up to \(180^\circ\)).

ABCD is a parallelogram. Find ∠CFG. Given that ∠AEB = 65° and ∠CFE = 18°.

Learn how to find ∠CFG in a parallelogram ABCD where ∠AEB = 65° and ∠CFE = 18°. This problem involves understanding the properties of parallelograms and the relationship between supplementary angles. Suitable for Grades 8-10 students studying geometry.

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