Math Problem Statement
Solution
The problem asks to find all values of in the interval where the given condition holds:
We will first solve for the principal angle using the inverse tangent function:
Next, we will find the general solutions for because the tangent function repeats every , and we are limited to the interval .
Let me compute the specific solutions for .It seems like I can’t do more advanced data analysis right now. Please try again later.
However, you can calculate the values using the following steps:
- Compute to get the principal solution.
- Then, use the fact that the tangent function repeats every to find the second solution within the interval :
- The second solution is .
If you calculate it, let me know if you'd like further help or explanations. Would you like to discuss any specific steps or concepts further?
Here are some related questions:
- How do you calculate the arctangent of a number?
- What is the significance of the principal angle in trigonometry?
- Why does the tangent function repeat every 180 degrees?
- How can you solve other trigonometric equations, such as for sine or cosine?
- How do you handle solutions to trigonometric equations outside of the interval?
Tip: When solving trigonometric equations, always check for all possible solutions within the specified interval by considering the periodicity of the function.
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Tangent Function
Inverse Trigonometric Functions
Formulas
θ = tan^(-1)(x)
θ_2 = θ_1 + 180°
Theorems
Periodic Nature of Tangent Function
General Solution for Tangent Equation
Suitable Grade Level
Grades 10-12
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