Math Problem Statement

cot pheta = 24/7 and sin pheta is less than 0, find the 5 remaining trig functions

Solution

To find the remaining trigonometric functions, let's first analyze the given information:

Step 1: Understand the quadrant

  1. cot(θ)=247\cot(\theta) = \frac{24}{7}. Since cotangent is positive, and sine is negative (sin(θ)<0\sin(\theta) < 0), the angle θ\theta is in the third quadrant, where both sine and cosine are negative.

Step 2: Relation between cotangent and tangent

cot(θ)=cos(θ)sin(θ)    tan(θ)=sin(θ)cos(θ)=1cot(θ)=724.\cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)} \implies \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} = \frac{1}{\cot(\theta)} = \frac{7}{24}.

Step 3: Use the Pythagorean identity to find the hypotenuse

Using the relation cot(θ)=adjacentopposite\cot(\theta) = \frac{\text{adjacent}}{\text{opposite}}, we construct a right triangle with:

  • Adjacent side = 24
  • Opposite side = 7

The hypotenuse rr is given by: r=adjacent2+opposite2=242+72=576+49=625=25.r = \sqrt{\text{adjacent}^2 + \text{opposite}^2} = \sqrt{24^2 + 7^2} = \sqrt{576 + 49} = \sqrt{625} = 25.

Step 4: Determine all trigonometric functions

Now we compute the six trigonometric functions:

  1. sin(θ)=oppositehypotenuse=725\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{-7}{25} (negative in the third quadrant).
  2. cos(θ)=adjacenthypotenuse=2425\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{-24}{25} (negative in the third quadrant).
  3. tan(θ)=sin(θ)cos(θ)=7/2524/25=724\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} = \frac{-7/25}{-24/25} = \frac{7}{24}.
  4. csc(θ)=1sin(θ)=17/25=257\csc(\theta) = \frac{1}{\sin(\theta)} = \frac{1}{-7/25} = -\frac{25}{7}.
  5. sec(θ)=1cos(θ)=124/25=2524\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{1}{-24/25} = -\frac{25}{24}.
  6. cot(θ)=cos(θ)sin(θ)=24/257/25=247\cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)} = \frac{-24/25}{-7/25} = \frac{24}{7}.

Final Answer:

  1. sin(θ)=725\sin(\theta) = -\frac{7}{25}
  2. cos(θ)=2425\cos(\theta) = -\frac{24}{25}
  3. tan(θ)=724\tan(\theta) = \frac{7}{24}
  4. csc(θ)=257\csc(\theta) = -\frac{25}{7}
  5. sec(θ)=2524\sec(\theta) = -\frac{25}{24}

Do you want me to provide a step-by-step explanation for any specific part?

Here are 5 related questions for further exploration:

  1. How do you determine the quadrant of an angle based on given trigonometric signs?
  2. Can you find the angle θ\theta in degrees or radians using inverse trigonometric functions?
  3. How do the signs of trigonometric functions vary in different quadrants?
  4. How can you verify the results using the Pythagorean identity?
  5. What are the implications of knowing the hypotenuse when calculating all trigonometric functions?

Tip: Always remember the ASTC rule (All Students Take Calculus) to determine which trigonometric functions are positive in each quadrant.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Quadrants and signs of trigonometric functions
Pythagorean theorem

Formulas

cot(θ) = cos(θ)/sin(θ)
sin²(θ) + cos²(θ) = 1
tan(θ) = sin(θ)/cos(θ)
csc(θ) = 1/sin(θ)
sec(θ) = 1/cos(θ)

Theorems

Pythagorean Theorem
Trigonometric identities

Suitable Grade Level

Grades 10-12