Math Problem Statement

Let Z ~ N(0,1). Find a so that P(Z > a) = 0.69.

Solution

The question asks to find aa such that P(Z>a)=0.69P(Z > a) = 0.69, where ZN(0,1)Z \sim N(0, 1), meaning that ZZ follows a standard normal distribution with mean 0 and standard deviation 1.

Solution steps:

  1. Understanding the problem:

    • You are given a probability for the tail end of the standard normal distribution.
    • This means we are looking for the value of aa such that the area to the right of aa under the normal curve equals 0.69.
  2. Using the cumulative distribution function (CDF):

    • For standard normal distributions, we use the cumulative distribution function (CDF), denoted Φ(a)\Phi(a), to find probabilities.
    • Given P(Z>a)=0.69P(Z > a) = 0.69, we have: P(Za)=10.69=0.31P(Z \leq a) = 1 - 0.69 = 0.31
    • We need to find the aa-value such that Φ(a)=0.31\Phi(a) = 0.31.
  3. Finding the z-score:

    • From standard normal distribution tables or using a calculator, the z-score corresponding to P(Za)=0.31P(Z \leq a) = 0.31 is approximately a=0.50a = -0.50.

Thus, the value of aa is approximately -0.50.

Would you like more details on any part of the solution?

Here are 5 related questions to expand your understanding:

  1. How is the CDF of a normal distribution calculated?
  2. Why is P(Z>a)=0.69P(Z > a) = 0.69 converted to P(Za)=0.31P(Z \leq a) = 0.31?
  3. What is the inverse CDF, and how does it help in solving problems like this?
  4. How would you solve this problem if the distribution was not standard normal?
  5. How can you use technology (like a calculator or software) to find the z-score?

Tip:

When working with normal distributions, always remember that the total area under the curve is 1, and you can convert tail probabilities to cumulative probabilities easily by subtracting from 1.

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Math Problem Analysis

Mathematical Concepts

Probability
Statistics
Standard Normal Distribution

Formulas

Cumulative Distribution Function (CDF)
P(Z > a) = 1 - P(Z ≤ a)

Theorems

Standard Normal Distribution Properties

Suitable Grade Level

College/University level (Statistics or Probability courses)