Math Problem Statement
by constructing a different table and using the second order differences as constant, find the sixth term(p) and the seventh term(q) of the sequence $8,12,2929,42,\cdots$
Solution
To solve for the 6th term () and 7th term () of the sequence , using the method of second-order differences, we'll follow these steps:
Step 1: Compute the first differences.
The first difference is the difference between consecutive terms in the sequence.
Step 2: Compute the second differences.
The second difference is the difference between consecutive values of the first differences.
Step 3: Assume the second differences are constant.
We are told that the second differences remain constant, so we assume the second difference continues to be .
Thus, the second differences are: .
Step 4: Extend the first differences.
To find the next first differences, we add the second differences to the existing first differences:
- After , add :
- After , add :
Thus, the first differences become: .
Step 5: Extend the sequence.
To find the 6th and 7th terms, we add the first differences to the current sequence values:
- The 5th term (after 42) is:
- The 6th term () is:
Thus, the 6th term is .
Now, for the 7th term ():
- The next first difference is .
- The 7th term () is:
Thus, the 7th term is .
Final Answer:
- (the 6th term)
- (the 7th term)
Would you like further details or have any questions?
Here are 5 related questions:
- How can second-order differences be applied to quadratic sequences?
- What if the second-order differences were not constant? How would that affect the solution?
- Can you explain the relationship between first, second, and third-order differences?
- How can you use this method for sequences with fractional terms?
- What are some real-world applications of difference methods?
Tip: Second-order differences suggest that the underlying rule of the sequence may be quadratic in nature.
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Math Problem Analysis
Mathematical Concepts
Sequences
Second-order Differences
Algebra
Formulas
First differences: T(n) = T(n+1) - T(n)
Second differences: Δ² = Δ(T(n+1)) - Δ(T(n))
Theorems
Difference Method for Polynomial Sequences
Suitable Grade Level
Grades 9-10
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