Math Problem Statement
Solution
The problem describes the motion of a ship in two segments and asks for the final bearing of the ship from the pier. Let's break it down step by step:
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First Leg:
- The ship travels on a bearing of for 75 Nautical Miles (NM).
- This means the ship moves southeast, forming an angle of east of due south.
-
Second Leg:
- After turning around, the ship moves on a bearing of for 53 Nautical Miles.
- This leg moves the ship northeast, forming an angle of east of due north.
Steps to solve:
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Convert bearings to Cartesian coordinates: Bearings can be transformed into directions on an XY-plane where North corresponds to the positive y-axis, and East corresponds to the positive x-axis.
- First leg:
- Second leg:
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Find the total displacement: Add the x and y components from both legs to get the overall displacement vector.
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Determine the bearing: Using trigonometry, the final bearing of the ship from the pier can be found by calculating the angle of the displacement vector from the north-south axis. If the displacement is in the first quadrant (both x and y positive), the bearing will be .
Let me calculate the values.The final bearing of the ship from the pier is approximately .
This means the ship is almost directly east of the pier with a slight deviation to the north.
Would you like further details or explanations on any part of this solution? Here are five related questions you might find interesting:
- How do you calculate the bearing when given two or more legs of a journey?
- Why is the tangent inverse function used to calculate the final bearing?
- How would this calculation change if the journey took place on a curved surface (like Earth)?
- What is the importance of converting bearings to Cartesian coordinates?
- How would the solution change if the ship traveled westward instead?
Tip: Bearings are typically measured clockwise from the north. When calculating bearings from coordinates, always adjust the angle to fit this convention.
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Vector Addition
Bearings
Coordinate Geometry
Formulas
x1 = d1 * sin(angle1)
y1 = d1 * cos(angle1)
x2 = d2 * sin(angle2)
y2 = d2 * cos(angle2)
theta = tan^(-1)(x_total / y_total)
Theorems
Pythagorean theorem for vector components
Inverse tangent function
Suitable Grade Level
Grades 9-12