The expression you've provided is $4x^2 - 9$. This is a quadratic expression and can be factored using the difference of squares method.

Solution:

The expression can be rewritten as: $4x^2 - 9 = (2x)^2 - 3^2$ Using the difference of squares formula, $a^2 - b^2 = (a - b)(a + b)$, we get: $4x^2 - 9 = (2x - 3)(2x + 3)$

So, the factorized form of $4x^2 - 9$ is $(2x - 3)(2x + 3)$.

Would you like more details or have any questions?

Related Questions:

1. How do you factorize a quadratic expression that doesn't use the difference of squares?
2. Can you provide an example where the difference of squares method doesn't apply?
3. How do you solve the equation $4x^2 - 9 = 0$?
4. What are some real-life applications of factoring quadratic expressions?
5. How do you expand the expression $(2x - 3)(2x + 3)$ back to $4x^2 - 9$?

Tip: When dealing with quadratic expressions, always check if it can be factored using simple identities like the difference of squares before trying more complex methods.