Math Problem Statement
When three positive integers a , a, b , b, and c c are multiplied together, their product is 100. 100. Suppose a < b < c . a<b<c. In how many ways can the numbers be chosen?
0 0
1 1
2 2
3 3
4
Solution
We are tasked with finding the number of ways to choose three positive integers such that:
- ,
- .
Step 1: Prime factorization of
The prime factorization of is:
Thus, any must be factors of , and their product must still equal .
Step 2: List the factors of
The factors of are:
Step 3: Find distinct triplets
We now determine all possible sets of three factors where , and their product equals .
Case-by-case enumeration:
-
Case 1:
- ,
- ,
- ,
- .
Valid triplets: .
-
Case 2:
- .
Valid triplet: .
-
Case 3:
- .
No valid triplets.
Step 4: Count the number of triplets
The valid triplets are:
Thus, there are 4 ways to choose such that and .
Final Answer:
4
Would you like me to clarify any step or expand further?
Follow-up Questions:
- How do we handle cases where the integers are not distinct?
- What happens if one of the integers is fixed, e.g., ?
- How does the solution change for a different product, such as ?
- Can you explain the reasoning behind using prime factorization in problems like this?
- How can this approach be extended to solve for four or more integers?
Tip:
When solving factorization problems with constraints, always start by listing all factors and work systematically to avoid missing cases.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Prime Factorization
Inequalities
Formulas
Product of integers: a * b * c = 100
Theorems
Fundamental Theorem of Arithmetic
Suitable Grade Level
Grades 9-11
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