give me a math problem that includes factoring special products 

Here's a math problem that involves factoring special products:

**Problem:**

Factor the following expression completely:

\[
9x^2 - 16
\]

**Solution:**

To solve this, recognize that the expression is a difference of squares, which is a special product. The difference of squares formula is:

\[
a^2 - b^2 = (a - b)(a + b)
\]

In this case:

- \(a^2 = 9x^2\) which means \(a = 3x\)
- \(b^2 = 16\) which means \(b = 4\)

Now, apply the difference of squares formula:

\[
9x^2 - 16 = (3x - 4)(3x + 4)
\]

So, the factored form of the expression is:

\[
(3x - 4)(3x + 4)
\]

Would you like more details or have any questions about this?  

Here are some related questions:

1. How do you factor the sum of squares?
2. Can you factor \(x^4 - 1\) using the difference of squares?
3. How do you factor a perfect square trinomial?
4. What is the factored form of \(x^2 - 25\)?
5. How do you recognize a difference of cubes?

**Tip:** When factoring, always check if the expression can be simplified as a special product like a difference of squares or a perfect square trinomial.

give me a math problem that includes factoring special products

Learn how to factor the expression 9x^2 - 16 using the difference of squares method. This algebra problem focuses on recognizing and applying special products to simplify quadratic expressions. Suitable for students in Grades 8-10.

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