https://file.aiquickdraw.com/mathbot/file/172541429851446xhi74t.jpg

It seems that the text extraction from the image was unsuccessful. However, based on the visual content you uploaded, the expression looks like \( x^2 + 6x + 5 \).

To factor this quadratic expression, we are looking for two binomials of the form:

\[
(x + m)(x + n)
\]

where \( m \) and \( n \) are numbers that satisfy the conditions:
1. \( m + n = 6 \) (the coefficient of \( x \))
2. \( m \times n = 5 \) (the constant term)

The numbers that satisfy these conditions are \( 1 \) and \( 5 \), because:

\[
1 + 5 = 6
\]
\[
1 \times 5 = 5
\]

Thus, the factorization of \( x^2 + 6x + 5 \) is:

\[
(x + 1)(x + 5)
\]

Would you like more details or have any questions?

Here are five related questions you might find interesting:
1. How do you factor a quadratic expression when the leading coefficient is not 1?
2. What is the significance of the discriminant in factoring quadratics?
3. How can you use the quadratic formula to solve \( x^2 + 6x + 5 = 0 \)?
4. What are the roots of the equation \( x^2 + 6x + 5 = 0 \) after factoring?
5. How does the method of completing the square help in solving quadratic equations?

**Tip:** When factoring quadratic expressions, always check if the expression can be simplified or if a greatest common factor can be factored out first.

Learn how to factor the quadratic expression x^2 + 6x + 5 into two binomials. This solution involves key algebraic concepts and provides a detailed step-by-step approach, suitable for students in Grades 8-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation