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The given equation is:

\[
x^2 + 10x + 16 = 0
\]

We need to factor this quadratic equation. To factor it, we look for two numbers that multiply to give \( 16 \) (the constant term) and add up to \( 10 \) (the coefficient of \( x \)).

The pair of numbers that satisfy these conditions are \( 2 \) and \( 8 \), since:

\[
2 \times 8 = 16 \quad \text{and} \quad 2 + 8 = 10
\]

Thus, the factored form of the quadratic equation is:

\[
(x + 2)(x + 8) = 0
\]

Since the problem asks to enter the lesser number first, the answer would be:

\[
(x + 2)(x + 8) = 0
\]

Would you like more details on how factoring works or any further clarifications?

Here are 5 questions related to factoring quadratic equations:
1. What methods can you use to factor quadratic equations other than trial and error?
2. How can you check if a quadratic equation is factorable over integers?
3. What are the steps to solve the factored equation \( (x + 2)(x + 8) = 0 \)?
4. What is the relationship between the discriminant and factorability of a quadratic equation?
5. How would you factor a quadratic equation that does not have real solutions?

**Tip:** Always check your factored terms by expanding them to ensure they match the original quadratic expression.

Supply the numbers to write x^2 + 10x + 16 = 0 in its factored form. Enter the lesser number first.

Learn how to factor the quadratic equation x^2 + 10x + 16 = 0. This example involves finding two numbers that multiply to 16 and add up to 10, resulting in the factored form (x + 2)(x + 8) = 0. Suitable for students in Grades 7-9.

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