Math Problem Statement

ab+bc-xc

Solution

The expression you've provided is:

ab+bcxcab + bc - xc

This expression can be factored. Here's how:

  1. Group the terms involving common factors: ab+(bcxc)ab + (bc - xc) Notice that both bcbc and xc-xc have a common factor of cc.

  2. Factor out the common factor cc from the second group: ab+c(bx)ab + c(b - x)

So, the factored form of the expression is: ab+c(bx)ab + c(b - x)

Would you like more details or have any questions?

Related Questions:

  1. How would you factor 2ab+4bc2xc2ab + 4bc - 2xc?
  2. What happens if b=xb = x in the original expression?
  3. How do you factor expressions involving more variables, like ab+ac+adab + ac + ad?
  4. How does factoring work in quadratic expressions?
  5. What are the applications of factoring in solving equations?

Tip: When factoring expressions, always look for common factors first to simplify your calculations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Factoring
Grouping terms

Formulas

Factoring common terms: ab + bc - xc = ab + c(b - x)

Theorems

Distributive property
Factoring common terms

Suitable Grade Level

Grades 8-10