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To solve the given problem, we need to factorize the expression \(7 + 21\) as a product of two factors.

First, we can rewrite the expression:
\[ 7 + 21 \]

We can factor out the common factor, which is 7:
\[ 7 \times 1 + 7 \times 3 \]

Next, we use the distributive property to factor out the 7:
\[ 7(1 + 3) \]

Therefore, the correct expression that shows \(7 + 21\) written as a product of two factors is:
\[ 7(1 + 3) \]

Among the given choices:
- \(7(1 + 3)\)
- \(3(1 + 7)\)
- \(3(3 + 7)\)
- \(7(3 + 3)\)

The correct answer is:
\[ 7(1 + 3) \]

Would you like further details or have any questions?

Here are 5 related questions to further your understanding:
1. How do you identify the greatest common factor (GCF) of two numbers?
2. Can you factorize the expression \(14 + 35\) in a similar way?
3. What is the distributive property and how is it used in factoring?
4. How can you factorize the expression \(21 + 28\) using the GCF?
5. Why is it important to recognize common factors in algebraic expressions?

**Tip:** Always look for the greatest common factor when trying to factorize expressions. This can simplify the process and help you identify the factors more easily.

Which expression shows 7 + 21 written as a product of two factors?

Learn how to factor the expression 7 + 21 as a product of two factors using the distributive property. This problem demonstrates factoring with a common factor and is suitable for Grade 6 students.

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