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The problem asks to factor the given factor from the expression. The expression is:

\[
\frac{1}{9x}, \quad \frac{2}{9x} - \frac{1}{9}
\]

### Step 1: Identify the common factor
From the first two terms, we can see that both have a common factor of \(\frac{1}{9x}\). 

- The first term is \(\frac{1}{9x}\).
- The second term can be rewritten as: 
  \[
  \frac{2}{9x} - \frac{1}{9} = \frac{1}{9}\left(\frac{2}{x} - 1\right)
  \]

### Step 2: Factoring
Now, we can factor out \(\frac{1}{9}\) from the expression. The expression becomes:

\[
\frac{1}{9}\left(\frac{1}{x}, \quad \frac{2}{x} - 1\right)
\]

So, the factored expression is:

\[
\boxed{\frac{1}{9}\left(\frac{1}{x}, \frac{2}{x} - 1\right)}
\]

Would you like more details on this step or clarification?

Here are 5 related questions for practice:

1. How do you find the greatest common factor between two terms?
2. How do you factor an expression with multiple variables?
3. How can you rewrite fractions with common denominators?
4. What does it mean to factor a constant from an expression?
5. How do you simplify expressions with fractions?

**Tip:** When factoring, always look for the greatest common factor (GCF) across all terms before simplifying the expression further.

Factor the given factor from the expression: \( \frac{1}{9x}, \quad \frac{2}{9x} - \frac{1}{9} \).

Learn how to factor common terms in algebraic fractions with the expression \( \frac{1}{9x}, \frac{2}{9x} - \frac{1}{9} \). This detailed solution covers key algebra concepts like factoring and working with fractions. Suitable for students in Grades 9-10.

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