The expression given is \(9y^2 - 4\). This can be factored using the difference of squares formula. The difference of squares formula states:

\[
a^2 - b^2 = (a - b)(a + b)
\]

Here, \(9y^2\) can be written as \((3y)^2\) and \(4\) as \(2^2\). Therefore:

\[
9y^2 - 4 = (3y)^2 - 2^2 = (3y - 2)(3y + 2)
\]

So, the factored form of the expression is:

\[
9y^2 - 4 = (3y - 2)(3y + 2)
\]

Would you like any further details or explanations?

Here are 5 related questions to explore further:

1. How would you factor \(16y^2 - 25\)?
2. What is the expanded form of \((3y - 2)(3y + 2)\)?
3. Can you factor \(y^4 - 16\) using the difference of squares?
4. What are the roots of the equation \(9y^2 - 4 = 0\)?
5. How does the difference of squares method apply to complex numbers?

**Tip:** When factoring polynomials, always check first if the expression can be simplified using the difference of squares, as it’s a quick and reliable method.

Discover how to factor the expression 9y^2 - 4 by applying the difference of squares formula. This algebraic problem involves understanding the difference of squares theorem and is suitable for students in Grades 8-10.

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