The expression \(w^2 - 6w + 5\) factors as:

\[
(w - 5)(w - 1)
\]

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Here are 5 related questions:
1. What are the roots of the equation \(w^2 - 6w + 5 = 0\)?
2. How would you expand \((w - 5)(w - 1)\) to verify the factorization?
3. What is the sum of the roots of \(w^2 - 6w + 5 = 0\)?
4. What is the product of the roots of \(w^2 - 6w + 5 = 0\)?
5. How can you use the quadratic formula to solve \(w^2 - 6w + 5 = 0\)?

**Tip:** When factoring a quadratic, look for two numbers that multiply to the constant term and add to the coefficient of the linear term.

Learn how to factor the quadratic expression w^2 - 6w + 5 with a detailed step-by-step solution. This problem covers key algebraic concepts, including factoring quadratic expressions and using the quadratic formula. Suitable for students in Grades 7-9.

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