Math Problem Statement

Factor by grouping: x^3 + 4x^2 - 9x - 36

Solution

The given expression to factor by grouping is:

x3+4x29x36x^3 + 4x^2 - 9x - 36

We will attempt to group terms and factor the expression.

Step 1: Group the terms

Group the terms in pairs:

(x3+4x2)(9x+36)(x^3 + 4x^2) - (9x + 36)

Step 2: Factor out the greatest common factor (GCF) from each group

For the first group x3+4x2x^3 + 4x^2, the GCF is x2x^2:

x2(x+4)x^2(x + 4)

For the second group 9x36-9x - 36, the GCF is 9-9:

9(x+4)-9(x + 4)

Step 3: Factor the common binomial

Now the expression looks like this:

x2(x+4)9(x+4)x^2(x + 4) - 9(x + 4)

Since both terms contain (x+4)(x + 4), we can factor that out:

(x+4)(x29)(x + 4)(x^2 - 9)

Step 4: Factor the difference of squares

The expression x29x^2 - 9 is a difference of squares, which can be factored as:

x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3)

Final factored form:

(x+4)(x3)(x+3)(x + 4)(x - 3)(x + 3)

The factored form of the given expression is:

(x+4)(x3)(x+3)(x + 4)(x - 3)(x + 3)

Would you like any further details or have any questions?

Here are some related questions:

  1. What is the difference of squares rule?
  2. How do you identify common factors in algebraic expressions?
  3. Can you factor a cubic equation directly without grouping?
  4. How does factoring help in solving polynomial equations?
  5. What are other methods for factoring polynomials?

Tip: Always check for common factors before applying advanced factoring methods, as this simplifies the expression early on.

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Math Problem Analysis

Mathematical Concepts

Algebra
Factoring by Grouping
Difference of Squares

Formulas

x^2 - 9 = (x - 3)(x + 3)
Factoring common binomials

Theorems

Difference of Squares Theorem
Factor by Grouping

Suitable Grade Level

Grades 9-11