Math Problem Statement

The average price of a two bedroom apartment in downtown new york city during the real estate boom from 1994 to 2004 can be approximated by p(t) = 0.33e^0.16t million dollars (0<t<10), where t is time in years. (T=0 represents 1994) what was the average price of a two bedroom apartment in downtown new york city in 2023? (Round your answer to two significant digits.)

How fast was the price increasing?

___ million dollars per year

Solution

To calculate the average price of a two-bedroom apartment in 2023, we need to first determine the value of tt corresponding to the year 2023. Since t=0t = 0 represents 1994:

t=20231994=29t = 2023 - 1994 = 29

The price function is given as:

p(t)=0.33e0.16tp(t) = 0.33e^{0.16t}

Step 1: Calculate p(29)p(29)

Substitute t=29t = 29 into the equation:

p(29)=0.33e0.1629p(29) = 0.33e^{0.16 \cdot 29}

Evaluate this using a calculator:

p(29)=0.33e4.64p(29) = 0.33e^{4.64}

Using e4.64103.56e^{4.64} \approx 103.56:

p(29)=0.33103.56=34.17million dollarsp(29) = 0.33 \cdot 103.56 = 34.17 \, \text{million dollars}

The average price of a two-bedroom apartment in downtown New York City in 2023 is approximately 34 million dollars.


Step 2: How fast was the price increasing in 2023?

The rate of change of the price is given by the derivative of p(t)p(t):

p(t)=ddt(0.33e0.16t)=0.330.16e0.16tp'(t) = \frac{d}{dt} \left( 0.33e^{0.16t} \right) = 0.33 \cdot 0.16e^{0.16t}

Substitute t=29t = 29:

p(29)=0.330.16e4.64p'(29) = 0.33 \cdot 0.16 \cdot e^{4.64}

Using e4.64103.56e^{4.64} \approx 103.56:

p(29)=0.330.16103.56=5.46million dollars per yearp'(29) = 0.33 \cdot 0.16 \cdot 103.56 = 5.46 \, \text{million dollars per year}

The price was increasing at a rate of approximately 5.5 million dollars per year in 2023.


Final Results:

  1. Average price in 2023: 34million dollars\mathbf{34} \, \text{million dollars}
  2. Rate of increase in 2023: 5.5million dollars per year\mathbf{5.5} \, \text{million dollars per year}

Would you like further details or explanations?
Here are 5 related questions for exploration:

  1. How does the rate of change vary with time tt?
  2. What was the average price in 1994?
  3. How would the model change if t=0t = 0 represented a different year?
  4. What does the exponential growth rate imply about housing markets?
  5. How accurate is this model for predictions beyond 2004, given its domain of validity?

Tip: Exponential growth models can rapidly diverge from reality for long-term predictions; always assess their assumptions!

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Derivative Calculations
Growth Rate Analysis

Formulas

Exponential function p(t) = 0.33e^(0.16t)
Derivative of exponential function p'(t) = 0.33 * 0.16 * e^(0.16t)

Theorems

Properties of Exponential Functions
Derivative Rules for Exponential Functions

Suitable Grade Level

Grades 11-12