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To express the final result after applying a 15% increase \( n \) times to the initial value of 750, we can model it using exponential growth.

1. The initial value is 750.
2. Each time a 15% increase is applied, the value is multiplied by \( 1 + 0.15 = 1.15 \).
3. After \( n \) increases, the total multiplication factor will be \( 1.15^n \).

Therefore, the expression for the final result after \( n \) increases is:

\[
750 \times 1.15^n
\]

This represents the value after increasing 750 by 15% a total of \( n \) times.

Would you like more details, or do you have any questions?

Here are some related questions for further exploration:
1. What happens if the percentage increase changes to 10%?
2. How would the formula change if there was a 15% decrease each time instead?
3. How would you compute the value after 5 increases?
4. What if the increase is applied continuously rather than in discrete steps?
5. How does this concept relate to compound interest?

**Tip:** Exponential growth models, like the one in this problem, are commonly used in finance, biology, and physics to describe how quantities grow over time when a constant percentage change is applied.

750 is increased by 15%. The result is then increased by 15%, and so on. In total, the increase is applied n times. Write an expression to represent the final result of this process.

Explore how to model repeated 15% increases on the value of 750. Learn the exponential growth formula for calculating the final result after n increases. Suitable for Grades 8-10 students, this problem covers key concepts in algebra and exponential functions.

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