Math Problem Statement

  1. Identify the exponential functions (i) x e (ii) e x (iii) x 2 (iv) 2x (v) x √ 3
  2. What is the range of the function f(x) = 3x ? (i) (−∞,∞) (ii) (−∞, 0) ∪ (0,∞) (iii) (0,∞) (iv) [0,∞)
  3. Evaluate the expression  1 + 1 x x for the given values of x. Round your answers to 10 decimal places in questions (i) through (iv), and give the exact value for question (v). (i) 10 (ii) 100 (iii) 1000 (iv) 10000 (v) x → ∞
  4. The continuous compounding formula is (i) P ert (ii) P(1 + r n ) nt Where P is the initial invested amount, r the annual interest rate, n the number of compoundings per year, and t the number of years.

Solution

Let's break down each question to provide answers and explanations.

1. Identify the exponential functions

Exponential functions are those of the form f(x)=aebxf(x) = a \cdot e^{bx} or f(x)=abxf(x) = a \cdot b^x, where ee or any constant is raised to a variable exponent.

(i) xex^e: Not exponential (This is a power function where a variable is raised to a constant power.) (ii) exe^x: Exponential (The base ee is raised to the variable xx.) (iii) x2x^2: Not exponential (Again, this is a power function.) (iv) 2x2^x: Exponential (The base 2 is raised to the variable xx.) (v) x3x^{\sqrt{3}}: Not exponential (Another power function.)

So, the exponential functions are:

  • (ii) exe^x
  • (iv) 2x2^x

2. What is the range of the function f(x)=3xf(x) = 3^x?

The function f(x)=3xf(x) = 3^x is an exponential function where the base 33 is greater than 1. For such functions:

  • As xx approaches negative infinity, f(x)f(x) approaches 0 but never reaches it.
  • As xx approaches positive infinity, f(x)f(x) increases without bound.

So, the range is (0,)(0, \infty).

Correct answer: (iii) (0, \infty)

3. Evaluate the expression (1+1x)x\left(1 + \frac{1}{x}\right)^x for the given values of xx.

This expression approaches the mathematical constant ee as xx increases.

Let's calculate for each value:

(i) For x=10x = 10: (1+110)10=(1.1)102.5937424601\left(1 + \frac{1}{10}\right)^{10} = \left(1.1\right)^{10} \approx 2.5937424601

(ii) For x=100x = 100: (1+1100)100=(1.01)1002.7048138294\left(1 + \frac{1}{100}\right)^{100} = \left(1.01\right)^{100} \approx 2.7048138294

(iii) For x=1000x = 1000: (1+11000)10002.7169239322\left(1 + \frac{1}{1000}\right)^{1000} \approx 2.7169239322

(iv) For x=10000x = 10000: (1+110000)100002.7181459268\left(1 + \frac{1}{10000}\right)^{10000} \approx 2.7181459268

(v) As xx approaches infinity, (1+1x)x\left(1 + \frac{1}{x}\right)^x approaches the exact value ee: e2.7182818285e \approx 2.7182818285

4. The continuous compounding formula

The continuous compounding formula is given by: (i) Pert\text{(i)}\ P \cdot e^{rt} Where:

  • PP is the initial invested amount,
  • rr is the annual interest rate,
  • tt is the number of years.

The second option, P(1+rn)ntP(1 + \frac{r}{n})^{nt}, is the formula for compound interest, not continuous compounding.

So, the correct formula for continuous compounding is (i).


Would you like more details on any of these solutions? Here are five questions to explore these topics further:

  1. What are the differences between exponential and power functions?
  2. How do you determine the range of an exponential function with different bases?
  3. Why does the expression (1+1x)x\left(1 + \frac{1}{x}\right)^x approach ee as xx increases?
  4. How does the compound interest formula change when the interest is compounded quarterly, monthly, or daily?
  5. What are some real-world applications of continuous compounding?

Tip: When working with exponential functions, always pay attention to the base, as it determines the behavior of the function over its domain.

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Math Problem Analysis

Mathematical Concepts

Exponential functions
Range of exponential functions
Limits and approximation to e
Continuous compounding interest

Formulas

f(x) = e^x
f(x) = 2^x
f(x) = 3^x
Limit: (1 + 1/x)^x → e as x → ∞
Continuous compounding: P * e^rt

Theorems

Limit definition of e
Exponential growth properties

Suitable Grade Level

Grades 10-12